8X8 in the LED dot matrix display column, its first move smoothly from left to right three times, followed by the right-to-left move three times smooth, smooth Mobile again from top to bottom three times, the last bottom-up three times smooth move, so the cycle Go on.
1. Programming content
8X8 principle of dot matrix LED note: 8X8 dot matrix needs a total of 64 light-emitting diodes, light emitting diodes and each line is a good place and out of the line crossing, when the corresponding out of a 1-level home, a line Purchase 0 level, corresponding to light emitting diode; therefore, to achieve a cylindrical light of the law, as shown in Figure 49, as a counterpart of a vertical column, or a corresponding act of a horizontal column, so to achieve Liang-chu of the methods described below:
A vertical column: corresponds to a buy out, and the line scanning method is used to achieve.
A horizontal column: 0 corresponding to the home line, and out of the scanning method is used to achieve.
2. Hardware circuit
3. Compilation of source
ORG 00H
START: NOP
MOV R3,#3
LOP2: MOV R4,#8
MOV R2,#0
LOP1: MOV P1,#0FFH
MOV DPTR,#TABA
MOV A,R2
MOVC A,@A+DPTR
MOV P3,A
INC R2
LCALL DELAY
DJNZ R4,LOP1
DJNZ R3,LOP2
MOV R3,#3
LOP4: MOV R4,#8
MOV R2,#7
LOP3: MOV P1,#0FFH
MOV DPTR,#TABA
MOV A,R2
MOVC A,@A+DPTR
MOV P3,A
DEC R2
LCALL DELAY
DJNZ R4,LOP3
DJNZ R3,LOP4
MOV R3,#3
LOP6: MOV R4,#8
MOV R2,#0
LOP5: MOV P3,#00H
MOV DPTR,#TABB
MOV A,R2
MOVC A,@A+DPTR
MOV P1,A
INC R2
LCALL DELAY
DJNZ R4,LOP5
DJNZ R3,LOP6
MOV R3,#3
LOP8: MOV R4,#8
MOV R2,#7
LOP7: MOV P3,#00H
MOV DPTR,#TABB
MOV A,R2
MOVC A,@A+DPTR
MOV P1,A
DEC R2
LCALL DELAY
DJNZ R4,LOP7
DJNZ R3,LOP8
LJMP START
DELAY: MOV R5,#10
D2: MOV R6,#20
D1: MOV R7,#248
DJNZ R7,$
DJNZ R6,D1
DJNZ R5,D2
RET
TABA: DB 0FEH,0FDH,0FBH,0F7H,0EFH,0DFH,0BFH,07FH
TABB: DB 01H,02H,04H,08H,10H,20H,40H,80H
END
4. C51 language source
#include
unsigned char code taba[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
unsigned char code tabb[]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80};
void delay(void)
{
unsigned char i,j;
for(i=10;i>0;i--)
for(j=248;j>0;j--);
}
void delay1(void)
{
unsigned char i,j,k;
for(k=10;k>0;k--)
for(i=20;i>0;i--)
for(j=248;j>0;j--);
}
void main(void)
{
unsigned char i,j;
while(1)
{
for(j=0;j<3;j++) //from left to right 3 time
{
for(i=0;i<8;i++)
{
P3=taba[i];
P1=0xff;
delay1();
}
}
for(j=0;j<3;j++) //from right to left 3 time
{
for(i=0;i<8;i++)
{
P3=taba[7-i];
P1=0xff;
delay1();
}
}
for(j=0;j<3;j++) //from top to bottom 3 time
{
for(i=0;i<8;i++)
{
P3=0x00;
P1=tabb[7-i];
delay1();
}
}
for(j=0;j<3;j++) //from bottom to top 3 time
{
for(i=0;i<8;i++)
{
P3=0x00;
P1=tabb[i];
delay1();
}
}
}
}
